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One of the key benefits of exception handling is that it enables your program to respond to an error and then continue running For example, consider the following example that divides the elements of one array by the elements of another If a division-by-zero occurs, a DivideByZeroException is generated In the program, this exception is handled by reporting the error and then continuing with execution Thus, attempting to divide by zero does not cause an abrupt runtime error resulting in the termination of the program Instead, it is handled gracefully, allowing program execution to continue

// Handle error gracefully and continue using System; class ExcDemo3 { static void Main() { int[] numer = { 4, 8, 16, 32, 64, 128 }; int[] denom = { 2, 0, 4, 4, 0, 8 }; for(int i=0; i < numerLength; i++) { try { ConsoleWriteLine(numer[i] + " / " + denom[i] + " is " + numer[i]/denom[i]); } catch (DivideByZeroException) { // Catch the exception ConsoleWriteLine("Can't divide by Zero!"); } } } }

1364 Fixed Convolution Convolution can be applied in several ways to improve cam pro les The most effective way that Gupta and Wiederrich (1983) identi ed they called xed convolution In this method we set d = d, d = 1, b = b = b/2 in Eqs (1367a and b) In this case, the nature of w is not changed during the convolutions The velocity curve is obtained from Eq (1367a) as vi +1 ( d , b ,q ) = vi ( d , b 2,q ) * w(1, b 2,q ) and the Fourier transform from Eq (1367b) as Vi +1 ( d , b , k ) = Vi ( d , b 2, k ) W (1, b 2, k ) The cumulative effect of m convolutions is obtained as follows: Vm ( d , b , k ) = W (1, b 2, k ) W (1, b 4, k ) W (1, b 2 m , k ) V0 ( d , b 2 m , k ) (1370) It is seen from Eq (1363b) and (1370) that the residual response, Rm(d,b,k) = |Vm(d,b,k)|, after m convolutions is dominated by the modi er function w(d,b,q), and the starting function v0(d,b,q) has only a small in uence From the de nition of v(1, b, q), it follows that v(1, 0, q) is a delta function (area = 1, function vanishes for q < 0- and q > 0+) Its transform |V(1,0,k,)| = 1 As m , a limiting residual response is thus obtained from Eq (1370)

For the ASP version:

Part I:

The output from the program is shown here:

(1368)

Part III:

This example makes another important point: Once an exception has been handled, it is removed from the system Therefore, in the program, each pass through the loop enters the try block anew any prior exceptions have been handled This enables your program to handle repeated errors

You can associate more than one catch clause with a try In fact, it is common to do so However, each catch must catch a different type of exception For example, the program shown here catches both array boundary and divide-by-zero errors:

When you log in to InfoView, the server first validates your user ID and password Your user ID and password may be specific to BusinessObjects XI or may be determined by another authentication source These other authentication sources may be the same as your LAN login or a third-party directory server that you use for all corporate applications Before beginning the login process, ensure you know the correct authentication source

(1369)

// Use multiple catch clauses using System; class ExcDemo4 { static void Main() { // Here, numer is longer than denom int[] numer = { 4, 8, 16, 32, 64, 128, 256, 512 }; int[] denom = { 2, 0, 4, 4, 0, 8 }; for(int i=0; i < numerLength; i++) { try { ConsoleWriteLine(numer[i] + " / " + denom[i] + " is " + numer[i]/denom[i]); } catch (DivideByZeroException) { ConsoleWriteLine("Can't divide by Zero!"); } catch (IndexOutOfRangeException) { ConsoleWriteLine("No matching element found"); } } } }

This program produces the following output: