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Since operating systems themselves are often also implemented as multiple threads, coordination between executing threads or processes is important both to people writing operating systems ( systems programmers ) and applications programmers This synchronization problem occupied a great deal of computer science research during the 1960s, 1970s, and 1980s Several solutions have been developed Dekker offered the first software solution to the problem in 1965, and a simplification by Peterson was published in 1981 These solutions involved shared variables and employed busy waiting (ie, the waiting process or thread had to wait continually check to see if the condition had changed) While these papers were groundbreaking, one would not use this approach today For one thing, these approaches are limited to situations where only two processes are cooperating, and for another, the busy wait is wasteful of CPU time.

public class Ex1406 public class TestLinearProbing { private static final int MASK = 0x7FFFFFFF; // 2^32-1 private static final int CAPACITY = 11; private static int size = 0; private static boolean[] used = new boolean[CAPACITY]; public static void main(String[] args) { printHash("Rad"); printHash("Uhr"); printHash("Ohr"); printHash("Tor"); printHash("Hut"); printHash("Tag"); printHash("Eis"); printHash("Ast"); printHash("Zug"); printHash("Hof"); printHash("Mal"); } private static void printHash(String word) { System.out.printf("hash(%s) = %d, load = %d%%%n", word, hash(word), 100*size/CAPACITY); } private static int hash(Object object) { ++size; int h = (object.hashCode() & MASK) % CAPACITY; while (used[h]) { System.out.printf("%d, ", h); h = (h+1)%CAPACITY; } used[h] = true; return h; } }

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A first impression is a critically defining moment. The instant one person first moves into the presence of another, an opinion is formed. Even before you utter any words, you open a dialogue and have spoken volumes through image and body language. The strong first impression that Barack Obama makes reminds us that body movement and image speak a language to the audience as potent as anything said out loud. Indeed, a highly influential executive coach and author of the book, CEO Material, D.A. Benton, once asked a group of young leaders at McKinsey & Company to imagine what they would do if they wanted to make people around them believe they were blind, even though they were not. She prodded them to consider how they would try to look and act. Perhaps they would wear a pair of dark glasses, get a white cane and use that cane to feel their way across the floor. They might walk slowly or haltingly, displaying a bit of uncertainty about the path ahead. They might even

The output is:

A hardware approach to synchronization is relatively simple, but does have the limitation that it, too, requires a busy wait All that is necessary is a single machine instruction that tests some condition and also sets the condition in the same instruction execution cycle Since it can t be interrupted, such a test-and-set instruction can be used for coordination In pseudocode, here is what a test-and-set instruction does: boolean testAndSet( boolean lock ) { if( !lock ) { lock = true; return true; } else return false; } This code says: The routine name is testAndSet, and it will return either true or false (a boolean value) testAndSet operates on a variable we will call lock , and lock can have the value true or false (it s a boolean variable)..

hash(Rad) = 3, load = 9% hash(Uhr) = 4, load = 18% hash(Ohr) = 2, load = 27% hash(Tor) = 8, load = 36% hash(Hut) = 5, load = 45% 3, 4, 5, hash(Tag) = 6, load = 54%

CHAP. 8]

CHAP. 6]

5, 6, hash(Eis) = 7, load = 63% 3, 4, 5, 6, 7, 8, hash(Ast) = 9, load = 72% 9, hash(Zug) = 10, load = 81% 3, 4, 5, 6, 7, 8, 9, 10, hash(Hof) = 0, load = 90% 2, 3, 4, 5, 6, 7, 8, 9, 10, 0, hash(Mal) = 1, load = 100% The size field contains the number of items hashed into the table. The used[] array flags which components are occupied in the table. The printHash() method prints the hash table index and the

resulting load factor as a percent. When linear probing kicks in, each successive index number probe is printed. As seen in Example 8.4, the collision occurs with the insertion of "Tag" at line 14. This program shows that it had three collisions (at index numbers 3, 4, and 5) before finding a free hash location at index 6. After that insertion, the table is 54 percent full. Every item after that also collides. And of course, as the table fills up, the number of collisions becomes more frequent. The last item, "Mal", has 10 collisions. That means that thereafter, every time this item is accessed it will have to search every one of the 11 items before it is found; clearly an O(n) process. Notice the index wraparound on the insertion of "Mal": 2, 3, 4, 5, 6, 7, 8, 9, 10, 0, 1.

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